INTEGRATION FORMULA WITH QUESTION
INTEGRATION FORMULA RAJESH ROYAL
FORMULA
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ncert conic section exercise solution / ncert chapter 11 exercise 11.1 solution /
conic section ncert book full solution conic section exercise full solution ]]]]™℗ Solutions for Class 11 Maths Chapter 11 EXERCISE 11.1 PAGE NO: 241 In each of the following Exercise 1 to 5, find the equation of the circle with 1. Centre (0, 2) and radius 2 Solution: Given: Centre (0, 2) and radius 2 Let us consider the equation of a circle with centre (h, k) and Radius r is given as (x – h) 2 + (y – k) 2 = r 2 So, centre (h, k) = (0, 2) and radius (r) = 2 The equation of the circle is (x – 0) 2 + (y – 2) 2 = 2 2 x 2 + y 2 + 4 – 4y = 4 x 2 + y 2 – 4y = 0 ∴ The equation of the circle is x 2 + y 2 – 4y = 0 2. Centre (–2, 3) and radius 4 Solution: Given: Centre (-2, 3) and radius 4 Let us consider the equation of a circle with centre (h, k) and Radius r is given as (x – h) 2 + (y – k) 2 = r 2 So, centre (h, k) = (-2, 3) and radius (r) = 4 The equation of the circle is (x + 2) 2 + (y – 3) 2 = (4) 2 x...
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